WebFeb 8, 2024 · Answer: (D) 55°. Explanation: Since, quadrilateral circumscribing a circle subtends supplementary angles at the centre of the circle. ∴∠AOB + ∠COD = 180°. 125° + ∠COD = 180°. ∠COD = 180° – 125° = 55°. Question 3. In the given figure, AB is a chord of the circle and AOC is its diameter, such that ∠ACB = 50°. WebAug 28, 2024 · selected Aug 29, 2024 by Shyam01. Best answer. (D) 55°. ABCD is a quadrilateral circumscribing the circle. We know that, the opposite sides of a quadrilateral …
In the given figure, if ∠AOB=125∘, then ∠COD is equal to
WebAug 24, 2024 · In Fig. 9.3, if ∠AOB = 125°, then ∠COD is equal to (A) 62.5° (B) 45° (C) 35° (D) 55°. ← Prev Question Next Question →. 0 votes. 10.7k views. asked Aug 24, 2024 in … WebFeb 3, 2024 · In Fig. 9.3, if ∠AOB = 125°, then ∠COD is equal to (A) 62.5° (B) 45° (C) 35° (D) 55° ... In Fig., rays OA, OB, OC, OD and OE have the common endpoint, O. Show, that ∠AOB +∠BOC +∠COD +∠DOE + ∠EOA = 360°. asked Apr 17, 2024 in Lines and Angles by Madhuwant (38.1k points) lines and angles; flash carro
Nitrogen removal with the physiological stratification of cathodic ...
WebABCD is a quadrilateral delineating the circle We realize that, the contrary sides of a quadrilateral d. elineating a circle subtend strengthening points at the focal point of the … Webare 4 cm and 5 cm, then the length of each chord of one circle which is tangent to the other circle is (A) 3 cm (B) 6 cm (C) 9 cm (D) 1 cm 2. In Fig. 9.3, if ∠AOB = 125°, then ∠COD is equal to (A) 62.5° (B) 45° (C) 35° (D) 55° 3. In Fig. 9.4, AB is a chord of the circle and AOC is its diameter such that ∠ACB = 50°. If AT is the WebApr 11, 2024 · The LSV measurements showed that the currents in the used cathodes were significantly decreased (Fig. 3 A), indicating that the electro-catalytic ability in the used cathode was inhibited because of the cathodic biofilm formations.The catalytic ability of the used cathode under 300 Ω was slightly less than that under 10 and 1000 Ω in a potential … flash cars 76